document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=588169>Question 588169</A>: <I><SPAN STYLE=\"word-break: break-all;\"> suppose we know that the sum of two numbers is 24. The second number is 6 less than the first. Write a system of equations and solve it to find the number. <BR>\n" );
document.write( "Is it like this x-6=24 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #374395 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=374395\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You don't need a \"system of equations\", just one equation will do.\r<BR>\n" );
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document.write( "x = one number<BR>\n" );
document.write( "x - 6 = second number {second number is 6 less than first}\r<BR>\n" );
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document.write( "x + x - 6 = 24 {sum of two numbers is 24}<BR>\n" );
document.write( "2x - 6 = 24 {combined like terms}<BR>\n" );
document.write( "2x = 30 {added 6 to both sides}<BR>\n" );
document.write( "x = 15 {divided both sides by 2}<BR>\n" );
document.write( "x - 6 = 9 {substituted 15, in for x, into x - 6}\r<BR>\n" );
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document.write( "15 and 9 are the two numbers<BR>\n" );
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