document.write( "Question 55170This question is from textbook TRIGONOMETRY
\n" ); document.write( ": PLEASE HELP ME WITH THIS PROBLEM I CANNOT FIGURE IT OUT IVE BEEN TRYING FOR DAYS:
\n" ); document.write( "The amount of a radioactive tracer remaining after t days is given A=Ao e^-0.058t, where Ao is the starting amount at the beginning of the time period. How many days will it take for one half of the original amount to decay?
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Algebra.Com's Answer #37435 by Hook(36)\"\" \"About 
You can put this solution on YOUR website!
You've got the following formula \"A=Ao+e%5E%28-0.058t%29\" and you want to know when half of the crap decays. Ok...so what that says in math-speak is:
\n" ); document.write( "\"A+=+Ao%2F2\"\r
\n" ); document.write( "\n" ); document.write( "Let's plug that into the original equation:\r
\n" ); document.write( "\n" ); document.write( "\"Ao%2F2=Ao+e%5E%28-0.058t%29\"
\n" ); document.write( "The Ao terms cancel out of each side, leaving
\n" ); document.write( "\"1%2F2+=+e%5E%28-0.058t%29\"\r
\n" ); document.write( "\n" ); document.write( "You just have to solve for t.
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