document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=587999>Question 587999</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, could you please help me with this exercise?\r<BR>\n" );
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document.write( "The perimeter is 96m.<BR>\n" );
document.write( "a=42m<BR>\n" );
document.write( "b=(10/17)*c<BR>\n" );
document.write( "Find the area.\r<BR>\n" );
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document.write( "It's about a normal triangle..not a rectangular one.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #374342 by </B><A HREF=/tutors/aboutme.mpl?userid=seliva-m><B>seliva-m(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=seliva-m><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=374342\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve c using P=a+b+c, where p=96,a=42,b=10/17*c:<BR>\n" );
document.write( "96=42+(10/17)c+c<BR>\n" );
document.write( "-27/17c=-54, divide both side by -27/17; c=34<BR>\n" );
document.write( "for b, subst. c=34 in b=10/17*c ; b=20\r<BR>\n" );
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document.write( "therefore sides of this triangle are 42,34,20 respectively, knowing longest side=42 w/c is also the base and obtaining 1/2 of it we can solve for h by P.T<BR>\n" );
document.write( "h=sqrt of 34^2-21^2 ; h=26.74\r<BR>\n" );
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document.write( "A=1/2*a*h ; 1/2*42*26.74<BR>\n" );
document.write( "area therefore is 561.54 sq. meter<BR>\n" );
document.write( "hope i got it correct </SPAN>\n" );
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