document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=587956>Question 587956</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The equation of curve is y=ax^n. Given that the points (2,9) and (3,4) lie on the curve, calculate the value of a and n. \r<BR>\n" );
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document.write( "9=a(2)^n <BR>\n" );
document.write( "n=log2 (9/a) <BR>\n" );
document.write( "4=a(3)^n <BR>\n" );
document.write( "n=log3 (4/a)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #374318 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=374318\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 9=a(2)^n ___ log(9) = log(a) + n log(2)\r<BR>\n" );
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document.write( "4=a(3)^n  ___ log(4) = log(a) + n log(3)\r<BR>\n" );
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document.write( "subtracting ___ log(9) - log(4) = n log(2) - n log(3) ___ log(9/4) = n log(2/3)\r<BR>\n" );
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document.write( "log[(2/3)^-2] = n log(2/3) ___ -2 log(2/3) = n log(2/3) ___ -2 = n\r<BR>\n" );
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document.write( "substituting ___ 9 = a(2^-2) ___ 9 = a(1/4) ___ 36 = a </SPAN>\n" );
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