document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=6802>Question 6802</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplify the algebraic expression\r<BR>\n" );
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document.write( "4[6-4(x-y)+ 6x]-16y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #3743 by </B><A HREF=/tutors/aboutme.mpl?userid=glabow><B>glabow(165)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=glabow><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=3743\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Simplify 4[6-4(x-y)+6x]-16y<BR>\n" );
document.write( "You evaluate exponents and radicals first. There are none. Whew!<BR>\n" );
document.write( "Next, evaluate groups. There are two groups. One is contained in the other. That's why the different type of bracketing was used. It need not have been, however. I like to evaluate the contained groups first, so I would do <BR>\n" );
document.write( "-4(x-y) first, giving -4x + 4y.<BR>\n" );
document.write( "The expression then becomes<BR>\n" );
document.write( "4[6-4x+4y+6x]-16y.<BR>\n" );
document.write( "The other group, 4[6-4x+4y+6x], gives 24-16x+16y+24x.<BR>\n" );
document.write( "The entire expression is now 24-16x+16y+24x-16y.<BR>\n" );
document.write( "Addition and subtraction always done last, giving<BR>\n" );
document.write( "24 + 8x.<BR>\n" );
document.write( "Of course, to complete the simplification you would factor out a common value of 8, giving<BR>\n" );
document.write( "8(3+x). </SPAN>\n" );
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