document.write( "Question 587847: Solve the equation: loga^x-loga^(x-5)=loga^6
\n" ); document.write( "log of a to x minus log of a to x-5 equals lof of a to the six
\n" ); document.write( "We are supposed to use the properties of logarithms to solve this problem.
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Algebra.Com's Answer #374289 by lwsshak3(11628)\"\" \"About 
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Solve the equation: loga^x-loga^(x-5)=loga^6
\n" ); document.write( "log of a to x minus log of a to x-5 equals lof of a to the six
\n" ); document.write( "We are supposed to use the properties of logarithms to solve this problem.
\n" ); document.write( "**
\n" ); document.write( "loga^x-loga^(x-5)=loga^6
\n" ); document.write( "loga^x-loga^(x-5)-loga^6=0
\n" ); document.write( "loga^x-(loga^(x-5)+loga^6)=0
\n" ); document.write( "place under a single log
\n" ); document.write( "log[(a^x)/a^(x-5)*a^6]=0
\n" ); document.write( "convert to exponential form: base(10) raised to log of number(0)=number(a^x)/a^(x-5)*a^6
\n" ); document.write( "10^0=(a^x)/a^(x-5)*a^6=1
\n" ); document.write( "(a^x)=a^(x-5)*a^6
\n" ); document.write( "a^x=a^(x-5+6)=a^(x+1)
\n" ); document.write( "x=x+1
\n" ); document.write( "0≠1 (no solution)
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