document.write( "Question 587847: Solve the equation: loga^x-loga^(x-5)=loga^6
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document.write( "log of a to x minus log of a to x-5 equals lof of a to the six
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document.write( "We are supposed to use the properties of logarithms to solve this problem. \n" );
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Algebra.Com's Answer #374289 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Solve the equation: loga^x-loga^(x-5)=loga^6 \n" ); document.write( "log of a to x minus log of a to x-5 equals lof of a to the six \n" ); document.write( "We are supposed to use the properties of logarithms to solve this problem. \n" ); document.write( "** \n" ); document.write( "loga^x-loga^(x-5)=loga^6 \n" ); document.write( "loga^x-loga^(x-5)-loga^6=0 \n" ); document.write( "loga^x-(loga^(x-5)+loga^6)=0 \n" ); document.write( "place under a single log \n" ); document.write( "log[(a^x)/a^(x-5)*a^6]=0 \n" ); document.write( "convert to exponential form: base(10) raised to log of number(0)=number(a^x)/a^(x-5)*a^6 \n" ); document.write( "10^0=(a^x)/a^(x-5)*a^6=1 \n" ); document.write( "(a^x)=a^(x-5)*a^6 \n" ); document.write( "a^x=a^(x-5+6)=a^(x+1) \n" ); document.write( "x=x+1 \n" ); document.write( "0≠1 (no solution) \n" ); document.write( " |