document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=587871>Question 587871</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve this equation 5x^2+3x-2=0 I need to see the steps as I am struggling to understand how to solve this using the quadratic formula </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #374277 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=374277\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a=	5	,	b=	3	,	c=	-2	<BR>\n" );
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document.write( "b^2-4ac=9+40	<BR>\n" );
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document.write( "b^2-4ac=49		\r<BR>\n" );
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document.write( "sqrt(49)=7\r<BR>\n" );
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document.write( "x=(-b+-sqrt(b^2-4*a*c))/(2*a)<BR>\n" );
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document.write( "x1=(-b+sqrt(b^2-4*a*c))/(2*a)								<BR>\n" );
document.write( "x1=(-3+	7)/10			<BR>\n" );
document.write( "x1=	0.40	<BR>\n" );
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document.write( "x2=(-3-7) /10				<BR>\n" );
document.write( "x2=	-1.00							<BR>\n" );
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