document.write( "Question 587821: How many liters of a 40% solution must be mixed with 60 liters of a 70% solution to get a 50% solution? \n" ); document.write( "

Algebra.Com's Answer #374242 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"x\"$ = liters of 40% solution needed
\n" ); document.write( " $\"+.7%2A60+=+42+\"$ liters
\n" ); document.write( "given:
\n" ); document.write( " $\"+%28+.4x+%2B+42+%29+%2F+%28+x+%2B+60+%29+=+.5+\"$
\n" ); document.write( " $\"+.4x+%2B+42+=+.5%2A%28+x+%2B+60+%29+\"$
\n" ); document.write( " $\"+.4x+%2B+42+=+.5x+%2B+30+\"$
\n" ); document.write( " $\"+.1x+=+12+\"$
\n" ); document.write( " $\"+x+=+120+\"$
\n" ); document.write( "120 liters of the 40% solution are needed \n" ); document.write( "

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