document.write( "Question 587433: a sum of 6500 is invested, part of it at 6% interest and the remainder at 11%. If the interest earned by the 6% investment is 150 less that the interest earned by the 11% investment, find the amount invested at 6% rate. \n" ); document.write( "

Algebra.Com's Answer #374127 by stanbon(75887) $\"\"$ $\"About$

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a sum of 6500 is invested, part of it at 6% interest and the remainder at 11%. If the interest earned by the 6% investment is 150 less that the interest earned by the 11% investment, find the amount invested at 6% rate.
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\n" ); document.write( "6% interest: 0.06x dollars
\n" ); document.write( "----
\n" ); document.write( "11% interest: 0.11(6500-x) dollars
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\n" ); document.write( "Equation:
\n" ); document.write( "0.06x + 150 = 0.11(6500-x)
\n" ); document.write( "----
\n" ); document.write( "6x + 15000 = 11*6500 - 11x
\n" ); document.write( "----
\n" ); document.write( "17x = 11*6500-15000
\n" ); document.write( "17x = 56500
\n" ); document.write( "x = $3323.53 (amt. invested at 6%)
\n" ); document.write( "6500-x = $3176.47 (amt. invested at 11%)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "========== \n" ); document.write( "

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