document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=587391>Question 587391</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 10% acid solution and a 30% acid solution need to be mixed to make 20 gallons of a 22% acid solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #374115 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=374115\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Set up two equations: the first for the % solution and the second for the amount (gallons).  x = gallons of the first solution, and y = gallons of the second solution.<P><BR>\n" );
document.write( "Gallons:  x+y=20 s0 x = 20-y<BR>\n" );
document.write( "Solution: .1x +.3y = .22*20 = 4.4 | Substitute the x value from the first eq: 20-y<BR>\n" );
document.write( ".1(20-y) + .3y = 4.4<BR>\n" );
document.write( "2-.1y+.3y = 4.4<BR>\n" );
document.write( ".2y = 2.4<BR>\n" );
document.write( "y =12<P><BR>\n" );
document.write( "From the first equation x = 20-y = 20-12 = 8.<P><BR>\n" );
document.write( "8 gallons of the 10% solution and 12 gallons of the 30% solution.<P><BR>\n" );
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