document.write( "Question 587366: The product of two consecutive negative odd integers is 899. What is the value of the two integers? \n" ); document.write( "
Algebra.Com's Answer #374084 by dfrazzetto(283)\"\" \"About 
You can put this solution on YOUR website!
odd integers:\r
\n" ); document.write( "\n" ); document.write( "2n+1, 2n+3\r
\n" ); document.write( "\n" ); document.write( "(2n+1)(2n+3) = 899\r
\n" ); document.write( "\n" ); document.write( "4n^2 + 8n + 3 = 899\r
\n" ); document.write( "\n" ); document.write( "4n^2 + 8n + 3 - 899 = 0\r
\n" ); document.write( "\n" ); document.write( "4n^2 + 8n - 896 = 0\r
\n" ); document.write( "\n" ); document.write( "n^2 + 2n - 224 = 0 \r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B2x%2B-224+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%282%29%5E2-4%2A1%2A-224=900\".
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\n" ); document.write( " Discriminant d=900 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-2%2B-sqrt%28+900+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%282%29%2Bsqrt%28+900+%29%29%2F2%5C1+=+14\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%282%29-sqrt%28+900+%29%29%2F2%5C1+=+-16\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B2x%2B-224\" can be factored:
\n" ); document.write( " \"1x%5E2%2B2x%2B-224+=+1%28x-14%29%2A%28x--16%29\"
\n" ); document.write( " Again, the answer is: 14, -16.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B2%2Ax%2B-224+%29\"

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\n" ); document.write( "\n" ); document.write( "plugging either of the roots in for n gives\r
\n" ); document.write( "\n" ); document.write( "29 and 31\r
\n" ); document.write( "\n" ); document.write( "29 x 31 = 899
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