document.write( "Question 587103: what are the side lengths of a rectangle whos perimeter is 66 and its area is 216
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Algebra.Com's Answer #373991 by xdragonfight(116)![]() ![]() ![]() You can put this solution on YOUR website! 2L+2W=66 \n" ); document.write( "LxW=216\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so start with 2L+2W=66 lets solve for W \n" ); document.write( "2L+2W=66 \n" ); document.write( "-2L -2L \n" ); document.write( "2W=66-2L \n" ); document.write( "divide everything by 2 \n" ); document.write( "2w/2=w 66/2=33 -2L/2=-L \n" ); document.write( "so new equation is w=33-L ok lets start on the 2nd equation \n" ); document.write( "LxW=216 \n" ); document.write( "replace W with (33-L) \n" ); document.write( "Lx(33-L)=216 \n" ); document.write( "-L^2+33L=216 \n" ); document.write( "so L=9 \n" ); document.write( "ok lets find W now \n" ); document.write( "2(9)+2W=66 \n" ); document.write( "2W=48 \n" ); document.write( "W=24 \n" ); document.write( "L=9 \n" ); document.write( "24x9=216 \n" ); document.write( " \n" ); document.write( " |