document.write( "Question 587095: Two students take a college entrance exam known to have a normal distribution of scores. The students receive raw scores of 74 and 94, which correspond to z scores (often called the standardized scores) of -1 and 2.0, respectively. Find the mean and standard deviation of the distribution of raw exam scores. (Use five decimal places in the intermediate calculations. Round your final answers to 4 decimal places.) \n" ); document.write( "
Algebra.Com's Answer #373979 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Two students take a college entrance exam known to have a normal distribution of scores. The students receive raw scores of 74 and 94, which correspond to z scores (often called the standardized scores) of -1 and 2.0, respectively. Find the mean and standard deviation of the distribution of raw exam scores. (Use five decimal places in the intermediate calculations. Round your final answers to 4 decimal places.)
\n" ); document.write( "-----
\n" ); document.write( "Use the form x = z*s + u
\n" ); document.write( "74 = -1s + u
\n" ); document.write( "94 = 2s + u
\n" ); document.write( "------
\n" ); document.write( "Subtract and solve for \"s\":
\n" ); document.write( "3s = 20
\n" ); document.write( "s = 20/3
\n" ); document.write( "--------
\n" ); document.write( "Solve for \"u\":
\n" ); document.write( "74 = (-20/3) + u
\n" ); document.write( "u = 222/3 + 20/3
\n" ); document.write( "----
\n" ); document.write( "u = 242/3 = 80 2/3
\n" ); document.write( "========================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "======================== \n" ); document.write( "
\n" );