document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=587049>Question 587049</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle is 69 cm. Side a is 5 cm shorter than side b. Side c is twice as long as side a. Find the length of each side. I need to know how to do it in 2 equations. Thanx! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #373959 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=373959\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle is 69 cm. Side a is 5 cm shorter than side b. Side c is twice as long as side a. Find the length of each side. I need to know how to do it in 2 equations. <BR>\n" );
document.write( "----------------------------<BR>\n" );
document.write( "Equations:<BR>\n" );
document.write( "a = b-5<BR>\n" );
document.write( "c = 2a<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "a + b + c = 69<BR>\n" );
document.write( "a + (a+5) + 2a = 69<BR>\n" );
document.write( "4a + 5 = 69<BR>\n" );
document.write( "4a = 64<BR>\n" );
document.write( "a = 16<BR>\n" );
document.write( "b = a+5 = 21<BR>\n" );
document.write( "c = 2a = 32<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );