document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=586866>Question 586866</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the vertices of the hyperbola <BR>\n" );
document.write( " (x+2)^2 over 9  - (y-3)^2 over 25 = 1 are___<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #373929 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=373929\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the vertices of the hyperbola <BR>\n" );
document.write( "(x+2)^2 over 9 - (y-3)^2 over 25 = 1<BR>\n" );
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document.write( "Standard form of equation for a hyperbola with horizontal transverse axis:<BR>\n" );
document.write( "(x+h)^2/a^2-(y-k)^2/b^2=1, (h,k) being the (x,y) coordinates of the center.<BR>\n" );
document.write( "For given equation:<BR>\n" );
document.write( "(x+2)^2/9-(y-3)^2/25=1<BR>\n" );
document.write( "center:(-2,3)<BR>\n" );
document.write( "a^2=9<BR>\n" );
document.write( "a=&#8730;9=3<BR>\n" );
document.write( "Vertices=(-2±a,3)=(-2±3,3)=(-5,3) and (1,3)<BR>\n" );
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