document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=586833>Question 586833</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi i really need someone to solve it fast (2x-1)^2 - (x-4)^2 + 12x - 60 = 0\r<BR>\n" );
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document.write( "i know the answer is x = 5/-5  but i need to know how .\r<BR>\n" );
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document.write( "thanks !!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #373910 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=373910\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> working the first two terms as the difference of squares\r<BR>\n" );
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document.write( "(3x - 5)(x + 3) + 12x - 60 = 0 ___ 3x^2 + 4x - 15 + 12x - 60 = 0 ___ 3x^2 + 16x - 75 = 0\r<BR>\n" );
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document.write( "factoring ___ (3x + 25)(x - 3) = 0\r<BR>\n" );
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document.write( "the answer that you know, is not correct\r<BR>\n" );
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document.write( "you can plug x=5/-5 into the original equation, and see that it does not work </SPAN>\n" );
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