document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=55125>Question 55125</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If  x > 0, y > 0 and x > y is true, why is -x < -y ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37389 by </B><A HREF=/tutors/aboutme.mpl?userid=Hook><B>Hook(36)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Hook><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37389\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perhaps if I translate into English, the statement will be more obvious:\r<BR>\n" );
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document.write( "If x and y are both positive, and x is greater than y (ie...x is further to the right on the number line), then if I slap a negative sign on x and y, x must be less than y (ie...further left on the number line). \r<BR>\n" );
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document.write( "OR\r<BR>\n" );
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document.write( "if you have <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+%3E+y ALIGN=MIDDLE  ALT=\"x+%3E+y\"   DISABLED_style= \"max-width:90%; height:auto;\" > and multiply both sides by -1, you'll get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-x%3C-y ALIGN=MIDDLE  ALT=\"-x%3C-y\"   DISABLED_style= \"max-width:90%; height:auto;\" > (remember, multiplying by a negative number changes the direction of inequality signs..) </SPAN>\n" );
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