document.write( "Question 586649: I need to put this euqation into standard form. (Then find the center, vertices, foci, and asympotote- all those I know how to do. I just don't know how to put it in standard form, first!) Please help?! \r
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document.write( "Equation: 9x^2 - 4y^2 + 18x + 32y - 91 = 0 \r
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document.write( "So far I wrote down:
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document.write( "(9x^2 + 18x) + (-4y^2 + 32y) = 91
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document.write( "1/2 (2) = 1^2 = 1
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document.write( "1/2 (8) = 4^2 = 16
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document.write( "9(x^2x+1)-4(y^2-8y+16) = 91 + 16 + 1
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document.write( "9(x^2x+1)-4(y^2-8y+16) = 108\r
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document.write( "And, I am stuck after that... help??
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Algebra.Com's Answer #373848 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! I need to put this euqation into standard form. (Then find the center, vertices, foci, and asympotote- all those I know how to do. I just don't know how to put it in standard form, first!) Please help?! \n" ); document.write( "Equation: 9x^2 - 4y^2 + 18x + 32y - 91 = 0 \n" ); document.write( "complete the squares \n" ); document.write( "9(x^2+2x+1) - 4(y^2-8y+16)= 91+9-64 \n" ); document.write( "9(x+1)^2-4(y-4)^2=36 \n" ); document.write( "divide by 36 \n" ); document.write( "(x+1)^2/4-(y-4)^2/9=1 \n" ); document.write( "This is an equation of a hyperbola with horizontal transverse axis. \n" ); document.write( "center: (-1,4) \n" ); document.write( "a^2=4 \n" ); document.write( "b^2=9 \n" ); document.write( "I will let you do the rest as you said you knew how. \n" ); document.write( " |