document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=586626>Question 586626</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Find the volume and surface area for the cylinder.<BR>\n" );
document.write( "A cylinder with a circumference of 50 pi inches and height of 12 inches. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #373830 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=373830\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "Divide the circumference by <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 2\pi\"> to find the radius of the base.  Calculate the area of the base using <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \pi{r^2}\">.  The volume is the height times the area of the base.\r<BR>\n" );
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document.write( "The Lateral Surface Area is the height times the circumference of the base.  The Total Surface Area is the Lateral Surface Area plus 2 times the Area of the Base.\r<BR>\n" );
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document.write( "Since all dimensions are in inches, the volume will be in cubic inches and the area in square inches.  Whether you leave your answer in terms of <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \pi\"> or use some decimal approximation is up to you (or the directions your teacher/instructor/professor gave you).  If you do use a decimal approximation of <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \pi\"> then the appropriate action is to round to the nearest whole number because your given measurements are to the nearest whole number and you should never report the results of a calculation involving measurements to a greater precision than your least precise given (or observed) measurment.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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