document.write( "Question 586623: How would you solve this: mark has twice as many quarters as nickels and three more dimes than nickels. He has $4.20 in all. How many of each type of coin does he have? \n" ); document.write( "
Algebra.Com's Answer #373828 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "I would choose a variable to represent the number of nickels. Then I would write an expression in this variable that represented the number of quarters, and another expression in this variable that represented the number of dimes. I would multiply my variable by 5, the expression representing the number of quarters by 25, and the expression representing the number of dimes by 10. Then I would sum the last three expressions and set the sum equal to 420. Next I would solve the equation for the number of nickels. Finally, using the number of nickels that I just calculated, I would calculate the number of quarters and the number of dimes using the expressions developed earlier to represent those quantities. But that is just me. I don't know how you would do it.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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