document.write( "Question 586580: (log7)2x+5-(log7)3=(log7)45 \n" ); document.write( "

Algebra.Com's Answer #373823 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
(log7)2x+5-(log7)3=(log7)45
\n" ); document.write( "=(log7)2x+5-(log7)3-(log7)45=0
\n" ); document.write( "log7[(2x+5)/(3*45)]=0
\n" ); document.write( "convert to exponential form
\n" ); document.write( "7^0=(2x+5)/135=1
\n" ); document.write( "2x+5=135
\n" ); document.write( "2x=130
\n" ); document.write( "x=65 \n" ); document.write( "

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