document.write( "Question 586589: A motorcycle traveling at 60mph overtakes a car traveling at 30mph that had a three-hour head start. How far from the starting point are the two vehicles?
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document.write( "How do I put this into an algebraic equation and solve it? Thanks \n" );
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Algebra.Com's Answer #373815 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A motorcycle traveling at 60mph overtakes a car traveling at 30mph that had a three-hour head start. \n" ); document.write( " How far from the starting point are the two vehicles? \n" ); document.write( "How do I put this into an algebraic equation and solve it? \n" ); document.write( ":\r \n" ); document.write( "\n" ); document.write( "Let t = travel time of motorcycle \n" ); document.write( "then \n" ); document.write( "(t+3) = travel time of the car \n" ); document.write( ": \n" ); document.write( "Write a distance equation, dist = speed * time \n" ); document.write( "60t = 30(t+3) \n" ); document.write( "60t = 30t + 90 \n" ); document.write( "60t - 30t = 90 \n" ); document.write( "t = 90/30 \n" ); document.write( "t = 3 hrs for the motorcycle to overtake the car \n" ); document.write( "; \n" ); document.write( "Find this dist: 3 * 60 = 180 mi \n" ); document.write( "Check the dist: 6 * 30 = 180 mi \n" ); document.write( " \n" ); document.write( " |