document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=586596>Question 586596</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three consecutive intefers are such that the sum of the second and the third is one less than three times the first. find three integers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #373814 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=373814\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = first <BR>\n" );
document.write( "x + 1 = 2nd<BR>\n" );
document.write( "x + 2 = 3rd\r<BR>\n" );
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document.write( "x + 1 + x + 2 = 3x - 1 {sum of second and third is one less than three times first}<BR>\n" );
document.write( "2x + 3 = 3x - 1 {combined like terms}<BR>\n" );
document.write( "3 = x - 1 {subtracted 2x from both sides}<BR>\n" );
document.write( "x = 4 {added 1 to both sides}<BR>\n" );
document.write( "x + 1 = 5 {substituted 4, in for x, into x + 1}<BR>\n" );
document.write( "x + 2 = 6 {substituted 4, in for x, into x + 2}\r<BR>\n" );
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document.write( "4,5, and 6 are the three consecutive integers<BR>\n" );
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