document.write( "Question 55113: explain how the graph of y-5=(x-3)^2\r
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\n" ); document.write( "\n" ); document.write( "This is what I did.\r
\n" ); document.write( "\n" ); document.write( "y-5=(x-3)^2
\n" ); document.write( "y=(x-3)^2+5\r
\n" ); document.write( "\n" ); document.write( "answer: y=x^2 right 3 units and up 5\r
\n" ); document.write( "\n" ); document.write( "??? right or way off?
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Algebra.Com's Answer #37377 by rchill(405)\"\" \"About 
You can put this solution on YOUR website!
Always, always, always, solve for y first! Expanding our equation yields \"y-5=x%5E2-6x%2B9\". Adding 5 to both sides gives us \"y=x%5E2-6x%2B14\". Any polynomial of 2nd degree will plot to a parabola; here it is:
\n" ); document.write( "\"graph%28300%2C300%2C-2%2C10%2C-2%2C15%2Cx%5E2-6x%2B14%29\"
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