document.write( "Question 586130: Please help me solve this problem.
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\n" ); document.write( "\n" ); document.write( "jody is driving at a constant rate. she passes a milepost that displays a two-digit number. exactly on hour later, she passes a second milepost that displays the same two digits in the reverse order. one hour later, she passes a third milepost with the original two digits separated by a zero. what is her rate in miles per hour?
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Algebra.Com's Answer #373689 by sudhanshu_kmr(1152)\"\" \"About 
You can put this solution on YOUR website!
Let assume first number is xy ie. 10x+y\r
\n" ); document.write( "\n" ); document.write( "second number is 10y+x, \r
\n" ); document.write( "\n" ); document.write( "third number is 100x+ y\r
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\n" ); document.write( "\n" ); document.write( "Difference between first and second = distance between second and third.\r
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\n" ); document.write( "\n" ); document.write( "=> 10y +x -(10x+y) = 100x+y - (10y+x)\r
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\n" ); document.write( "\n" ); document.write( "after solving this we get, y = 6x\r
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\n" ); document.write( "\n" ); document.write( "so, only possible value of x is 1, otherwise y will become two digit number.\r
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\n" ); document.write( "\n" ); document.write( "so, numbers are 16, 61 and 106. \r
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\n" ); document.write( "\n" ); document.write( "speed = 61-16 = 45 miles per hour.\r
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\n" ); document.write( "\n" ); document.write( "if any doubt, feel free to ask....\r
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