document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=55073>Question 55073</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Joe has 37 coins (all nickels, dimes, and quarters) worth $5.50. He has 4 more quarters than nickels. How many dimes does Joe have?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37367 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37367\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Joe has 37 coins (all nickels, dimes, and quarters) worth $5.50. He has 4 more quarters than nickels. How many dimes does Joe have?<BR>\n" );
document.write( "================<BR>\n" );
document.write( "Let the number of nickels be \"x\"; Value of those coins is 5x cents.<BR>\n" );
document.write( "The number of quarters is \"x+4\" ; Value of those is 25(x+4)=25x+100 cents<BR>\n" );
document.write( "And number of dimes is \"37-x-(x+4)\"=\"33-2x\"; Value is 10(33-2x)=330-20x cents<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "value + value + value = 550 cents<BR>\n" );
document.write( "5x+25x+100+330-20x=550<BR>\n" );
document.write( "10x=120<BR>\n" );
document.write( "x=12 (number of nickels)<BR>\n" );
document.write( "x+4=16 (number of quarters)<BR>\n" );
document.write( "37-28=9(number of dimes)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );