document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=586247>Question 586247</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A chemist wants to mix some 34% alloy with some 70% alloy to produce 30 ounces of a 40% alloy. How many ounces of each strength should he use? \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #373665 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=373665\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist wants to mix some 34% alloy with some 70% alloy to produce 30 ounces of a 40% alloy. How many ounces of each strength should he use? <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "active + active = active<BR>\n" );
document.write( "0.34x + 0.70(30-x) = 0.40*30<BR>\n" );
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document.write( "34x + 70*30-70x = 40*30<BR>\n" );
document.write( "-36x = -30*30<BR>\n" );
document.write( "x = 25 ounces (amt. of 34% alloy needed)<BR>\n" );
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document.write( "70-25 = 55 ounces (amt. of 70% alloy needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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