document.write( "Question 586082: Hi! please help me factor this polynomial completely : \"n%5E5%2B216n%5E2\" \r
\n" ); document.write( "\n" ); document.write( "i know how to solve it up to the part \"n%5E2%28n%5E3%2B216%29\" but i do not know how to factor it completely \r
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Algebra.Com's Answer #373605 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Here's how you factor \"n%5E3%2B216\"\r
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\n" ); document.write( "\n" ); document.write( "\"n%5E3%2B216\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%28n%29%5E3%2B%286%29%5E3\" Rewrite \"n%5E3\" as \"%28n%29%5E3\". Rewrite \"216\" as \"%286%29%5E3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28n%2B6%29%28%28n%29%5E2-%28n%29%286%29%2B%286%29%5E2%29\" Now factor by using the sum of cubes formula. Remember the sum of cubes formula is \"A%5E3%2BB%5E3=%28A%2BB%29%28A%5E2-AB%2BB%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28n%2B6%29%28n%5E2-6n%2B36%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So \"n%5E3%2B216\" factors to \"%28n%2B6%29%28n%5E2-6n%2B36%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"n%5E3%2B216=%28n%2B6%29%28n%5E2-6n%2B36%29\"\r
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\n" ); document.write( "\n" ); document.write( "This means that \"n%5E5%2B216n%5E2\" completely factors to \"n%5E2%28n%2B6%29%28n%5E2-6n%2B36%29\"\r
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\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r
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