document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=55076>Question 55076</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For the following problem, I know A = l w, is it l=w+2 and A=60? 60=w+2(w) being the final?<BR>\n" );
document.write( "The length of a rectangle is 2 cm greater than twice its width.  If the area of the rectangle is 60 cm , find the length of the rectangle.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37355 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37355\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2 cm greater than twice its width.  If the area of the rectangle is 60 cm , find the length of the rectangle. <BR>\n" );
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document.write( "Length = 2width + 2 or 2w+2: correct<BR>\n" );
document.write( "Then Area = w(x+2): you need the parenthesis.<BR>\n" );
document.write( "w(2w+2)=60<BR>\n" );
document.write( "2w^2+2w-60=0<BR>\n" );
document.write( "w=[-2+-sqrt(4-4(2)(-60))]/4<BR>\n" );
document.write( "w=[-2+sqrt484]/4<BR>\n" );
document.write( "w=[(-2+22]/4<BR>\n" );
document.write( "w=5<BR>\n" );
document.write( "length = 2w+2=12<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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