document.write( "Question 585932: {x+2y+3z=6, y+2z=0, z=2} solve by substitution \n" ); document.write( "
Algebra.Com's Answer #373548 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! x+2y+3z=6 \n" ); document.write( "y+2z=0 \n" ); document.write( "z=2 \n" ); document.write( "solve by substitution \n" ); document.write( "------ \n" ); document.write( "z is given. \n" ); document.write( "Sub for z in the eqn 2, gives the solution for y. \n" ); document.write( "Sub for y & z in the 1st eqn to find x. \n" ); document.write( " \n" ); document.write( " |