document.write( "Question 585932: {x+2y+3z=6, y+2z=0, z=2} solve by substitution \n" ); document.write( "
Algebra.Com's Answer #373548 by Alan3354(69443)\"\" \"About 
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x+2y+3z=6
\n" ); document.write( "y+2z=0
\n" ); document.write( "z=2
\n" ); document.write( "solve by substitution
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\n" ); document.write( "z is given.
\n" ); document.write( "Sub for z in the eqn 2, gives the solution for y.
\n" ); document.write( "Sub for y & z in the 1st eqn to find x.
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