document.write( "Question 585879: The sum of 2 and 3 times the difference of a number and 5 is equal to 4 times the difference of a number and 1 \n" ); document.write( "
Algebra.Com's Answer #373522 by Schaman_Dempster(26)![]() ![]() You can put this solution on YOUR website! Let the number be x.\r \n" ); document.write( "\n" ); document.write( "Difference of the number and 5 = x -5\r \n" ); document.write( "\n" ); document.write( "2 times the difference of the number and 5 = 2(x - 5) \n" ); document.write( "3 times the difference of the number and 5 = 3(x - 5)\r \n" ); document.write( "\n" ); document.write( "Sum of 2 times and 3 times the difference of the number and 5 = 2(x - 5)+ 3(x-5) \n" ); document.write( "= 5( x- 5)\r \n" ); document.write( "\n" ); document.write( "Difference of the number and 1 is = x -1 \n" ); document.write( "4 times the difference of the number and 1 is = 4 (x -1)\r \n" ); document.write( "\n" ); document.write( "So, 5 (x -5) = 4(x -1) \n" ); document.write( "or 5x - 25 = 4x - 4 \n" ); document.write( "or 5x - 4x - 25 = -4 \n" ); document.write( "or x - 25 = -4 \n" ); document.write( "or x = 25 -4 \n" ); document.write( "or x = 21\r \n" ); document.write( "\n" ); document.write( "Hence, the number is 21 \n" ); document.write( " |