document.write( "Question 585879: The sum of 2 and 3 times the difference of a number and 5 is equal to 4 times the difference of a number and 1 \n" ); document.write( "
Algebra.Com's Answer #373522 by Schaman_Dempster(26)\"\" \"About 
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Let the number be x.\r
\n" ); document.write( "\n" ); document.write( "Difference of the number and 5 = x -5\r
\n" ); document.write( "\n" ); document.write( "2 times the difference of the number and 5 = 2(x - 5)
\n" ); document.write( "3 times the difference of the number and 5 = 3(x - 5)\r
\n" ); document.write( "\n" ); document.write( "Sum of 2 times and 3 times the difference of the number and 5 = 2(x - 5)+ 3(x-5)
\n" ); document.write( "= 5( x- 5)\r
\n" ); document.write( "\n" ); document.write( "Difference of the number and 1 is = x -1
\n" ); document.write( "4 times the difference of the number and 1 is = 4 (x -1)\r
\n" ); document.write( "\n" ); document.write( "So, 5 (x -5) = 4(x -1)
\n" ); document.write( "or 5x - 25 = 4x - 4
\n" ); document.write( "or 5x - 4x - 25 = -4
\n" ); document.write( "or x - 25 = -4
\n" ); document.write( "or x = 25 -4
\n" ); document.write( "or x = 21\r
\n" ); document.write( "\n" ); document.write( "Hence, the number is 21
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