document.write( "Question 585848: A mowed 3/4 at his lawn in 5/4 hours.B who works twice as fast finished the job.how many minutes did B work? \n" ); document.write( "
Algebra.Com's Answer #373497 by josmiceli(19441)\"\" \"About 
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If A mowed 3/4 of his lawn, there is 1/4 left
\n" ); document.write( "for B to mow
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\n" ); document.write( "If A mowed a lawn 4 times as large, it would take him
\n" ); document.write( "4 times longer, so
\n" ); document.write( "\"+4%2A%283%2F4%29+=+3+\" lawns take him \"+4%2A%285%2F4%29+=+5+\" hrs
\n" ); document.write( "1 lawn would take him 1/3 of that time, or \"+%281%2F3%29%2A5+=+5%2F3+\" hrs
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\n" ); document.write( "If B works twice as fast, he can mow 1 lawn in \"+%281%2F2%29%2A%285%2F3%29+=+5%2F6+\" hrs
\n" ); document.write( "But B only has to mow 1/4 of a lawn, so
\n" ); document.write( "B can mow it in \"+%281%2F4%29%2A%285%2F6%29+=+5%2F24+\" hrs
\n" ); document.write( "\"+5%2F24+\" hrs x \"+60+\" min/hr = 12.5 minutes
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