document.write( "Question 585645: Okay so for a car project I have this problem and I need to find out how long it would take for me to pay for the car to pay less than 125% of what it is worth.- A=P(1+r/12)^t. A= amount of money total i paid for the car,P= amount of loan i needed) r= interest rate and t= length of loan(in months)\r
\n" ); document.write( "\n" ); document.write( "For my particular case, I have: A= 26641.12, P= 21000, r= .0349 (3.49%), and t= 48. I know I have to use logarithms to get T down to find the time, but I'm stuck
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Algebra.Com's Answer #373478 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A=P(1+r/12)^t.
\n" ); document.write( " A= amount of money total i paid for the car,
\n" ); document.write( " P= amount of loan i needed)
\n" ); document.write( " r= interest rate and
\n" ); document.write( " t= length of loan(in months)
\n" ); document.write( ":
\n" ); document.write( "For my particular case, I have: A= 26641.12, P= 21000, r= .0349 (3.49%), and t= 48.
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\n" ); document.write( "you give t=48, but isn't that what we are trying to find here?
\n" ); document.write( "And 1.25 * 21000 = 26250
\n" ); document.write( ":
\n" ); document.write( "21000[1+(.0349/12))^t] = 26250
\n" ); document.write( ":
\n" ); document.write( "\"1.0029083%5Et\" = \"26250%2F21000\"
\n" ); document.write( "Using common logs
\n" ); document.write( "\"log%28%281.0029083%5Et%29%29\" = \"log%28%2826250%2F21000%29%29\"
\n" ); document.write( "The log equiv of exponents
\n" ); document.write( "\"t%2Alog%28%281.0029083%29%29\" = \"log%28%2826250%2F21000%29%29\"
\n" ); document.write( "find the logs
\n" ); document.write( "t * .00126 = .09691
\n" ); document.write( "t = \".09691%2F.00126\"
\n" ); document.write( "t = 76.9, pay it off in 76 months to pay less that $26250
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\n" ); document.write( "Check this, enter in you calc: 21000(1+(.0349/12))^76 results: $26,186.26 is what you'll pay in 76 months
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