document.write( "Question 585733: Please help me solve this equation:\r
\n" ); document.write( "\n" ); document.write( "2log(base4)x+3log(base8)x=10
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Algebra.Com's Answer #373456 by lwsshak3(11628)\"\" \"About 
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Please help me solve this equation:
\n" ); document.write( "2log(base4)x+3log(base8)x=10
\n" ); document.write( "convert to log base2 using change of base formula: log(new base)(x)/log(new base)(old base)
\n" ); document.write( "2log2(x)/log2(4)+3log2(x)/log2(8)=10
\n" ); document.write( "log2(4)=2
\n" ); document.write( "log2(8)=3
\n" ); document.write( "2log2(x)/2+3log2(x)/3=10
\n" ); document.write( "LCD=6
\n" ); document.write( "6log2(x)+6log2(x)=60
\n" ); document.write( "12log2(x)=60
\n" ); document.write( "log2(x)=60/12=5
\n" ); document.write( "x=2^5=32
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