document.write( "Question 585360: What is the vertex, directrix, and focal width of the parabola: x^2=36y \n" ); document.write( "
Algebra.Com's Answer #373452 by lwsshak3(11628)\"\" \"About 
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What is the vertex, directrix, and focal width of the parabola: x^2=36y
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\n" ); document.write( "Standard form of equation for a parabola that opens upwards: (x-h)^2=4p(y-k), (h,k) being the (x,y) coordinates of the vertex.
\n" ); document.write( "For given equation: x^2=36y
\n" ); document.write( "vertex: (0,0)
\n" ); document.write( "axis of symmetry: y-axis or x=0
\n" ); document.write( "4p=36
\n" ); document.write( "p=9
\n" ); document.write( "directrix: y=-9 (p units below the vertex on the axis of symmetry)
\n" ); document.write( "focus: (0,9)
\n" ); document.write( "focal width=4p=36
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