document.write( "Question 585360: What is the vertex, directrix, and focal width of the parabola: x^2=36y \n" ); document.write( "
Algebra.Com's Answer #373452 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! What is the vertex, directrix, and focal width of the parabola: x^2=36y \n" ); document.write( "** \n" ); document.write( "Standard form of equation for a parabola that opens upwards: (x-h)^2=4p(y-k), (h,k) being the (x,y) coordinates of the vertex. \n" ); document.write( "For given equation: x^2=36y \n" ); document.write( "vertex: (0,0) \n" ); document.write( "axis of symmetry: y-axis or x=0 \n" ); document.write( "4p=36 \n" ); document.write( "p=9 \n" ); document.write( "directrix: y=-9 (p units below the vertex on the axis of symmetry) \n" ); document.write( "focus: (0,9) \n" ); document.write( "focal width=4p=36 \n" ); document.write( " |