document.write( "Question 585573: William opened two investment accounts for his grandson's college fund. The first year, these investments, which totaled $18,000 yielded $831 in simple interest. Part of the money was invested at 5.5% and the rest at 4%. How much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #373438 by mananth(16949) You can put this solution on YOUR website! part I 5.50% per annum---x \n" ); document.write( "part II 4.00% per annum---y \n" ); document.write( " \n" ); document.write( "x+y=18000 ------------------------1 \n" ); document.write( "5.50%x +4.00%y=831 \n" ); document.write( "Multiply by 100 \n" ); document.write( "5.5x+4y=83100.00--------2 \n" ); document.write( " \n" ); document.write( "Multiply (1) by -5.5 \n" ); document.write( "we get \n" ); document.write( " \n" ); document.write( "-5.5 x -5.5 y= -99000.00 \n" ); document.write( " \n" ); document.write( "Add this to (2) \n" ); document.write( " \n" ); document.write( "-1.5 y=-15900 \n" ); document.write( " \n" ); document.write( "divide by -1.5 \n" ); document.write( " \n" ); document.write( "y=10600 \n" ); document.write( "$10,600 investment at 4.00% \n" ); document.write( "Balance $ 7400 investment at 5.50% \n" ); document.write( "CHECK \n" ); document.write( "10600 --------- 4.00% ------- 424.00 \n" ); document.write( "7400 ------- 5.50% ------- 407.00 \n" ); document.write( "Total -------------- 831.00 \n" ); document.write( " \n" ); document.write( " |