document.write( "Question 585556: A man invests $12,000 in two accounts. One account pays 10% per year. The other account pays 7% per year. How much was invested in each account, if the total interest earned in the first year was $960 \n" ); document.write( "

Algebra.Com's Answer #373436 by mananth(16946) $\"\"$ $\"About$

You can put this solution on YOUR website!
part I 10.00% per annum ---x
\n" ); document.write( "part II 7.00% per annum ---y
\n" ); document.write( "
\n" ); document.write( "x+y=12000 ------------------------1
\n" ); document.write( "10.00% x + 7.00% y= 960
\n" ); document.write( "Multiply by 100
\n" ); document.write( "10x+7y= 96000 --------2
\n" ); document.write( "
\n" ); document.write( "Multiply (1) by -10
\n" ); document.write( "we get
\n" ); document.write( "
\n" ); document.write( "-10x-10y=-120000.00
\n" ); document.write( "
\n" ); document.write( "Add this to (2)
\n" ); document.write( "
\n" ); document.write( "-3y= = -24000
\n" ); document.write( "
\n" ); document.write( "divide by -3
\n" ); document.write( "
\n" ); document.write( "y= 8000 investment at 7.00%
\n" ); document.write( "Balance 4000 investment at 10.00%
\n" ); document.write( "CHECK
\n" ); document.write( "8000 --------- 7.00% ------- 560.00
\n" ); document.write( "4000 ------- 10.00% ------- 400.00
\n" ); document.write( "Total -------------- 960.00
\n" ); document.write( " \n" ); document.write( "

\n" );