document.write( "Question 585605: A solution of 75% pesticide is to be mixed with a solution of 35% pesticide to form 440 liters of a 43% solution. How many liters of the 75% solution must be used? \n" ); document.write( "
Algebra.Com's Answer #373420 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A solution of 75% pesticide is to be mixed with a solution of 35% pesticide to form 440 liters of a 43% solution. How many liters of the 75% solution must be used? \n" ); document.write( "---------------------- \n" ); document.write( "Equation: \n" ); document.write( "active + active = active \n" ); document.write( "0.75x + 0.35(440-x) = 0.43*440 \n" ); document.write( "----- \n" ); document.write( "75x + 35*440 - 35x = 43*440 \n" ); document.write( "40x = 8*440 \n" ); document.write( "x = (1/5)*440 \n" ); document.write( "x = 88 liters (amt of 75% solution needed) \n" ); document.write( "---- \n" ); document.write( "440-x = 352 liters (amt. of 35% solution needed) \n" ); document.write( "================================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |