document.write( "Question 585605: A solution of 75% pesticide is to be mixed with a solution of 35% pesticide to form 440 liters of a 43% solution. How many liters of the 75% solution must be used? \n" ); document.write( "
Algebra.Com's Answer #373419 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Acid percent ---------------- quantity \n" ); document.write( "Pesticide type I 75.00% ---------------- x liters \n" ); document.write( "Pesticide type II} 35.00% ------ 440 - x liters \n" ); document.write( "Mixture 43.00% ---------------- 440 \n" ); document.write( " \n" ); document.write( "75.00%x+35.00%(440-x)=43.00% * 440 \n" ); document.write( "75x+35( 440-x)= 18920 \n" ); document.write( "75x+15400-35x=18920 \n" ); document.write( "75x-35x =18920-15400 \n" ); document.write( "40x= 3520 \n" ); document.write( "/ 40 \n" ); document.write( "x=88 liters 75.00% Pesticide type I \n" ); document.write( "352 liters 35.00% Pesticide type II} \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |