document.write( "Question 585600: Please help me solve this problem:\r
\n" ); document.write( "\n" ); document.write( "Five years ago, Dino was 1/5 as old as his father. Thirteen years from now, Dino will be half as old as his father. Find their present age.\r
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Algebra.Com's Answer #373416 by mananth(16946)\"\" \"About 
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Let dinos' age be x five years ago
\n" ); document.write( "father's age = 5x \r
\n" ); document.write( "\n" ); document.write( "After 13 years\r
\n" ); document.write( "\n" ); document.write( "dino's age = x+18
\n" ); document.write( "Father's age = 5x+18\r
\n" ); document.write( "\n" ); document.write( "2(x+18)= 5x+18\r
\n" ); document.write( "\n" ); document.write( "2x+36= 5x+18\r
\n" ); document.write( "\n" ); document.write( "5x-2x= 36-18
\n" ); document.write( "3x=18
\n" ); document.write( "/3
\n" ); document.write( "x= 6 years 5 years ago.\r
\n" ); document.write( "\n" ); document.write( "Now Dino's age = 5+5 = 10 years
\n" ); document.write( "Father's age 5 years ago = 5x= 30 years\r
\n" ); document.write( "\n" ); document.write( "Now Father's age = 35 years\r
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