document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=585567>Question 585567</A>: <I><SPAN STYLE=\"word-break: break-all;\">  when the sum of 8 and 18 times a positive number is subtracted from the square of the number, zero results.  Find the number?<BR>\n" );
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document.write( "w^2-(8w+18)=0<BR>\n" );
document.write( "w^2-8w-18=0 <BR>\n" );
document.write( "It said to find the number so, would I factor out the binomial and set both to zero and find the number that way?  I can't get it to factor out evenly. The closest I have got is (w-2)(w+9)=0\r<BR>\n" );
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document.write( "Can you please help me solve this\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #373398 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=373398\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Not w^2-(8w+18)=0 <BR>\n" );
document.write( "but <BR>\n" );
document.write( "w^2-(8+18w)=0 <BR>\n" );
document.write( "which still doesn't factor.<BR>\n" );
document.write( "  <BR>\n" );
document.write( "(w-9)^2-89 = 0<BR>\n" );
document.write( "w = 9-sqrt(89) and w = 9+sqrt(89)<BR>\n" );
document.write( "only the positive<BR>\n" );
document.write( "w=18.434<BR>\n" );
document.write( "no solution the way the problem is written.\r<BR>\n" );
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