document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=585507>Question 585507</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to know how to factor 21x^2(2x-3)+41x(2x-3)+10(2x-3). What I have done so far is to multiple and combine like terms. Is that right? Then i came up with 42x^3+82x^2+20x-186. Do I factor by grouping? The cube factor kinda freaks me out. Please help!! Thanking you so much for your help and input.  I dont just need answers, I really want to understand how I need to do this. Thank you.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #373384 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=373384\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> factor: 21x^2(2x-3) + 41x(2x-3) + 10(2x-3)<BR>\n" );
document.write( "Note that it is already grouped, each term contains (2x-3), so you can<BR>\n" );
document.write( "(2x-3)(21x^2 + 41x + 10)<BR>\n" );
document.write( "I would just leave it like this </SPAN>\n" );
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