document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=585411>Question 585411</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary. If the measure of one angle is 46 more than the measure of the other angle, find the measure of the two angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #373334 by </B><A HREF=/tutors/aboutme.mpl?userid=Schaman_Dempster><B>Schaman_Dempster(26)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Schaman_Dempster><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Schaman_Dempster><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=373334\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the two angles be x and y such that x>y.\r<BR>\n" );
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document.write( "Since they are supplementary angles, therefore x + y = 180   ---------(1)\r<BR>\n" );
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document.write( "Also,  x = y + 46   ------------ (2)\r<BR>\n" );
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document.write( "Plugging the value of x from equation (2) into equation (1), we get:\r<BR>\n" );
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document.write( "y + 46 + y = 180<BR>\n" );
document.write( "2y + 46 =180<BR>\n" );
document.write( "2y = 180 - 46<BR>\n" );
document.write( "2y = 134<BR>\n" );
document.write( "y = 67\r<BR>\n" );
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document.write( "Plugging back the value of y in equation (1),<BR>\n" );
document.write( "x = 67 + 46<BR>\n" );
document.write( "x = 113\r<BR>\n" );
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document.write( "Hence, the two angles are 67' and 113'\r<BR>\n" );
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document.write( "Hope this helps~! </SPAN>\n" );
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