document.write( "Question 585287: A firm starts work with 110 employees for the first week. The number of the employees rises by 6% per week. How many persons will be employed in the 20th week if the present rate of expansion continues.\r
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document.write( "I've tried using Sn=a(r^n - 1)/r^n-1 but can't get the right answer. \n" );
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Algebra.Com's Answer #373290 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A firm starts work with 110 employees for the first week. \n" ); document.write( " The number of the employees rises by 6% per week. \n" ); document.write( " How many persons will be employed in the 20th week if the present rate of expansion continues. \n" ); document.write( ": \n" ); document.write( "The multiplier for a 6% increase is 1.06, therefore \n" ); document.write( "; \n" ); document.write( "Total = \n" ); document.write( "Use a calc to find 1.06^20 \n" ); document.write( "T = 110 * 3.207 \n" ); document.write( "T ~ 353 employees in 20 weeks \n" ); document.write( " |