document.write( "Question 585287: A firm starts work with 110 employees for the first week. The number of the employees rises by 6% per week. How many persons will be employed in the 20th week if the present rate of expansion continues.\r
\n" ); document.write( "\n" ); document.write( "I've tried using Sn=a(r^n - 1)/r^n-1 but can't get the right answer.
\n" ); document.write( "

Algebra.Com's Answer #373290 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A firm starts work with 110 employees for the first week.
\n" ); document.write( " The number of the employees rises by 6% per week.
\n" ); document.write( " How many persons will be employed in the 20th week if the present rate of expansion continues.
\n" ); document.write( ":
\n" ); document.write( "The multiplier for a 6% increase is 1.06, therefore
\n" ); document.write( ";
\n" ); document.write( "Total = \"110%281.06%5E20%29\"
\n" ); document.write( "Use a calc to find 1.06^20
\n" ); document.write( "T = 110 * 3.207
\n" ); document.write( "T ~ 353 employees in 20 weeks
\n" ); document.write( "
\n" );