document.write( "Question 585308: A 60cm piece of wire is bent to form a right triangle. If the hypotenuse is 26cm long, what are legs of the right triangle? \n" ); document.write( "
Algebra.Com's Answer #373267 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Wire length = 60 cm\r \n" ); document.write( "\n" ); document.write( "right triangle is formed \n" ); document.write( "perimeter = 60 cm \n" ); document.write( "hypotenuse = 26\r \n" ); document.write( "\n" ); document.write( "so sum of legs = 60 -26 = 34cm\r \n" ); document.write( "\n" ); document.write( "let one leg be x \n" ); document.write( "other leg = 34-x\r \n" ); document.write( "\n" ); document.write( "(34-x)^2+x^2= 26^2\r \n" ); document.write( "\n" ); document.write( "1156-68x+x^2= 676\r \n" ); document.write( "\n" ); document.write( "2x^2-68x+1156-676=0\r \n" ); document.write( "\n" ); document.write( "2x^2-68x+480=0 \n" ); document.write( "/2 \n" ); document.write( "x^2-34x+240=0\r \n" ); document.write( "\n" ); document.write( "x^2-24x-10x+240=0\r \n" ); document.write( "\n" ); document.write( "x(x-24)-10(x-24)=0\r \n" ); document.write( "\n" ); document.write( "(x-24)(x-10)=0\r \n" ); document.write( "\n" ); document.write( "The legs are 24 & 10 cm \n" ); document.write( " |