document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=585306>Question 585306</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three forth of a number exeeds  it s one third by 15  find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #373261 by </B><A HREF=/tutors/aboutme.mpl?userid=Schaman_Dempster><B>Schaman_Dempster(26)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Schaman_Dempster><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Schaman_Dempster><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=373261\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the number be x.\r<BR>\n" );
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document.write( "So, we can set up the equation as:\r<BR>\n" );
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document.write( "(3/4)x = (1/3)x + 15\r<BR>\n" );
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document.write( "Solving for x:\r<BR>\n" );
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document.write( "3x = (4/3)x + 60   {Multiplying 4 on both the sides}\r<BR>\n" );
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document.write( "9x = 4x + 180         {Multiplying 3 on both the sides}\r<BR>\n" );
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document.write( "5x = 180<BR>\n" );
document.write( "x = 36\r<BR>\n" );
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document.write( "Hope this helps~! </SPAN>\n" );
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