document.write( "Question 585249: Mr. Wilson invested money in two accounts. His total investment was $20,000. If one account pays 2% in interest and the other pays 5% in interest, how much does he have in each account if he earned a total of $550 in interest in 1 year?\r
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document.write( "In the 2% account: $
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document.write( "In the 5% account: $
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Algebra.Com's Answer #373256 by mananth(16946)![]() ![]() You can put this solution on YOUR website! part I 2.00% per annum ---x \n" ); document.write( "part II 5.00% per annum ---y \n" ); document.write( " \n" ); document.write( "x + 1 y= 20000 ------------------------1 \n" ); document.write( "2.00% x + 5.00% y= 550 \n" ); document.write( "Multiply by 100 \n" ); document.write( "2 x + 5 y= = 55000.00 --------2 \n" ); document.write( " \n" ); document.write( "Multiply (1) by -2 \n" ); document.write( "we get \n" ); document.write( " \n" ); document.write( "-2 x -2 y= -40000.00 \n" ); document.write( " \n" ); document.write( "Add this to (2) \n" ); document.write( " \n" ); document.write( "0 x 3 y= = 15000 \n" ); document.write( " \n" ); document.write( "divide by 3 \n" ); document.write( " \n" ); document.write( "y = 5000 investment at 5.00% \n" ); document.write( "Balance 15000 investment at 2.00% \n" ); document.write( "CHECK \n" ); document.write( "5000 --------- 5.00% ------- 250.00 \n" ); document.write( "15000 ------- 2.00% ------- 300.00 \n" ); document.write( "Total -------------- 550.00 \n" ); document.write( " \n" ); document.write( " |