document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=585288>Question 585288</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the equation of parabola whose vertex at origin and directrix x=2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #373250 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=373250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the equation of parabola whose vertex at origin and directrix x=2<BR>\n" );
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document.write( "Standard form of equation for a parabola that opens leftwards(directrix is to the right of the vertex): <BR>\n" );
document.write( "(y-k)^2=-4p(x-h), (h,k) being the (x,y) coordinates of the vertex. <BR>\n" );
document.write( "For given parabola:<BR>\n" );
document.write( "vertex:(0,0)<BR>\n" );
document.write( "axis of symmetry: x-axis or y=0<BR>\n" );
document.write( "p=2 (distance from vertex to directrix on the axis of symmetry)<BR>\n" );
document.write( "equation of given parabola:<BR>\n" );
document.write( "y^2=-4px<BR>\n" );
document.write( "y^2=-8x<BR>\n" );
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