document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=585203>Question 585203</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 60 miles per hour and train B is traveling at 80 miles per hour. Train a passes a station at 7:15 P.M. If train B passes the same station at 7:30 P.M. at what time will train B catch up to train A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #373202 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=373202\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Train A  	60	mph				<BR>\n" );
document.write( "Train B  	80	mph				<BR>\n" );
document.write( "Train A  		07:15				<BR>\n" );
document.write( "Train B  		07:30				<BR>\n" );
document.write( "Difference in time=		15 minutes	=>	0.25	hours	<BR>\n" );
document.write( "Train A  	will have covered	15	miles	before	Train B  	starts  (0.25*60)<BR>\n" );
document.write( "catch up distance=		15	miles			<BR>\n" );
document.write( "catch up speed =		80	-60	mph		<BR>\n" );
document.write( "catch up speed =		20	mph			<BR>\n" );
document.write( "Catchup time = catchup distance/catch up speed						<BR>\n" );
document.write( "catch up time=		15	/	20		<BR>\n" );
document.write( "catch up time=		0.75	hours			<BR>\n" );
document.write( "They will meet at		08:45	pm			<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );