document.write( "Question 585029: Judith invested $13,000 for 1year, part at 10% interest and part at 9% interest. If she earned a total of $1150 in interest, howyvh did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #373191 by ankor@dixie-net.com(22740)\"\" \"About 
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udith invested $13,000 for 1year, part at 10% interest and part at 9% interest.
\n" ); document.write( "If she earned a total of $1150 in interest, how much did she invest at each rate?
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\n" ); document.write( "Let a = amt invested at 10%
\n" ); document.write( "Let b = amt invested at 9%
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\n" ); document.write( "The total investment equation
\n" ); document.write( "a + b = 13000
\n" ); document.write( "b = (13000-a), use this form for substitution
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\n" ); document.write( "The total interest equation
\n" ); document.write( ".10a + .09b = 1150
\n" ); document.write( "Replace b with (13000-a)
\n" ); document.write( ".10a + .09(13000-a) = 1150
\n" ); document.write( ".10a + 1170 - .09a = 1150
\n" ); document.write( "Right here we can see there is flaw in this problem
\n" ); document.write( ".10a - .09a = 1150 - 1170
\n" ); document.write( ".01a = -20, a negative here is not reasonable, check the source of the problem
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\n" ); document.write( "Anyway, this method should be helpful to you. C \n" ); document.write( "
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